Integrand size = 19, antiderivative size = 498 \[ \int \frac {x^7 \log (c+d x)}{a+b x^4} \, dx=\frac {c^3 x}{4 b d^3}-\frac {c^2 x^2}{8 b d^2}+\frac {c x^3}{12 b d}-\frac {x^4}{16 b}-\frac {c^4 \log (c+d x)}{4 b d^4}+\frac {x^4 \log (c+d x)}{4 b}-\frac {a \log \left (\frac {d \left (\sqrt {-\sqrt {-a}}-\sqrt [4]{b} x\right )}{\sqrt [4]{b} c+\sqrt {-\sqrt {-a}} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (\frac {d \left (\sqrt [4]{-a}-\sqrt [4]{b} x\right )}{\sqrt [4]{b} c+\sqrt [4]{-a} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (-\frac {d \left (\sqrt {-\sqrt {-a}}+\sqrt [4]{b} x\right )}{\sqrt [4]{b} c-\sqrt {-\sqrt {-a}} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (-\frac {d \left (\sqrt [4]{-a}+\sqrt [4]{b} x\right )}{\sqrt [4]{b} c-\sqrt [4]{-a} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \operatorname {PolyLog}\left (2,\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c-\sqrt {-\sqrt {-a}} d}\right )}{4 b^2}-\frac {a \operatorname {PolyLog}\left (2,\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c+\sqrt {-\sqrt {-a}} d}\right )}{4 b^2}-\frac {a \operatorname {PolyLog}\left (2,\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c-\sqrt [4]{-a} d}\right )}{4 b^2}-\frac {a \operatorname {PolyLog}\left (2,\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c+\sqrt [4]{-a} d}\right )}{4 b^2} \]
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Time = 0.58 (sec) , antiderivative size = 498, normalized size of antiderivative = 1.00, number of steps used = 23, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.421, Rules used = {272, 45, 2463, 2442, 266, 2441, 2440, 2438} \[ \int \frac {x^7 \log (c+d x)}{a+b x^4} \, dx=-\frac {a \operatorname {PolyLog}\left (2,\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c-\sqrt {-\sqrt {-a}} d}\right )}{4 b^2}-\frac {a \operatorname {PolyLog}\left (2,\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c+\sqrt {-\sqrt {-a}} d}\right )}{4 b^2}-\frac {a \operatorname {PolyLog}\left (2,\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c-\sqrt [4]{-a} d}\right )}{4 b^2}-\frac {a \operatorname {PolyLog}\left (2,\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c+\sqrt [4]{-a} d}\right )}{4 b^2}-\frac {a \log (c+d x) \log \left (\frac {d \left (\sqrt {-\sqrt {-a}}-\sqrt [4]{b} x\right )}{\sqrt {-\sqrt {-a}} d+\sqrt [4]{b} c}\right )}{4 b^2}-\frac {a \log (c+d x) \log \left (\frac {d \left (\sqrt [4]{-a}-\sqrt [4]{b} x\right )}{\sqrt [4]{-a} d+\sqrt [4]{b} c}\right )}{4 b^2}-\frac {a \log (c+d x) \log \left (-\frac {d \left (\sqrt {-\sqrt {-a}}+\sqrt [4]{b} x\right )}{\sqrt [4]{b} c-\sqrt {-\sqrt {-a}} d}\right )}{4 b^2}-\frac {a \log (c+d x) \log \left (-\frac {d \left (\sqrt [4]{-a}+\sqrt [4]{b} x\right )}{\sqrt [4]{b} c-\sqrt [4]{-a} d}\right )}{4 b^2}-\frac {c^4 \log (c+d x)}{4 b d^4}+\frac {c^3 x}{4 b d^3}-\frac {c^2 x^2}{8 b d^2}+\frac {x^4 \log (c+d x)}{4 b}+\frac {c x^3}{12 b d}-\frac {x^4}{16 b} \]
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Rule 45
Rule 266
Rule 272
Rule 2438
Rule 2440
Rule 2441
Rule 2442
Rule 2463
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {x^3 \log (c+d x)}{b}-\frac {a x^3 \log (c+d x)}{b \left (a+b x^4\right )}\right ) \, dx \\ & = \frac {\int x^3 \log (c+d x) \, dx}{b}-\frac {a \int \frac {x^3 \log (c+d x)}{a+b x^4} \, dx}{b} \\ & = \frac {x^4 \log (c+d x)}{4 b}-\frac {a \int \left (\frac {x \log (c+d x)}{2 \left (-\sqrt {-a} \sqrt {b}+b x^2\right )}+\frac {x \log (c+d x)}{2 \left (\sqrt {-a} \sqrt {b}+b x^2\right )}\right ) \, dx}{b}-\frac {d \int \frac {x^4}{c+d x} \, dx}{4 b} \\ & = \frac {x^4 \log (c+d x)}{4 b}-\frac {a \int \frac {x \log (c+d x)}{-\sqrt {-a} \sqrt {b}+b x^2} \, dx}{2 b}-\frac {a \int \frac {x \log (c+d x)}{\sqrt {-a} \sqrt {b}+b x^2} \, dx}{2 b}-\frac {d \int \left (-\frac {c^3}{d^4}+\frac {c^2 x}{d^3}-\frac {c x^2}{d^2}+\frac {x^3}{d}+\frac {c^4}{d^4 (c+d x)}\right ) \, dx}{4 b} \\ & = \frac {c^3 x}{4 b d^3}-\frac {c^2 x^2}{8 b d^2}+\frac {c x^3}{12 b d}-\frac {x^4}{16 b}-\frac {c^4 \log (c+d x)}{4 b d^4}+\frac {x^4 \log (c+d x)}{4 b}-\frac {a \int \left (-\frac {\log (c+d x)}{2 b^{3/4} \left (\sqrt {-\sqrt {-a}}-\sqrt [4]{b} x\right )}+\frac {\log (c+d x)}{2 b^{3/4} \left (\sqrt {-\sqrt {-a}}+\sqrt [4]{b} x\right )}\right ) \, dx}{2 b}-\frac {a \int \left (-\frac {\log (c+d x)}{2 b^{3/4} \left (\sqrt [4]{-a}-\sqrt [4]{b} x\right )}+\frac {\log (c+d x)}{2 b^{3/4} \left (\sqrt [4]{-a}+\sqrt [4]{b} x\right )}\right ) \, dx}{2 b} \\ & = \frac {c^3 x}{4 b d^3}-\frac {c^2 x^2}{8 b d^2}+\frac {c x^3}{12 b d}-\frac {x^4}{16 b}-\frac {c^4 \log (c+d x)}{4 b d^4}+\frac {x^4 \log (c+d x)}{4 b}+\frac {a \int \frac {\log (c+d x)}{\sqrt {-\sqrt {-a}}-\sqrt [4]{b} x} \, dx}{4 b^{7/4}}+\frac {a \int \frac {\log (c+d x)}{\sqrt [4]{-a}-\sqrt [4]{b} x} \, dx}{4 b^{7/4}}-\frac {a \int \frac {\log (c+d x)}{\sqrt {-\sqrt {-a}}+\sqrt [4]{b} x} \, dx}{4 b^{7/4}}-\frac {a \int \frac {\log (c+d x)}{\sqrt [4]{-a}+\sqrt [4]{b} x} \, dx}{4 b^{7/4}} \\ & = \frac {c^3 x}{4 b d^3}-\frac {c^2 x^2}{8 b d^2}+\frac {c x^3}{12 b d}-\frac {x^4}{16 b}-\frac {c^4 \log (c+d x)}{4 b d^4}+\frac {x^4 \log (c+d x)}{4 b}-\frac {a \log \left (\frac {d \left (\sqrt {-\sqrt {-a}}-\sqrt [4]{b} x\right )}{\sqrt [4]{b} c+\sqrt {-\sqrt {-a}} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (\frac {d \left (\sqrt [4]{-a}-\sqrt [4]{b} x\right )}{\sqrt [4]{b} c+\sqrt [4]{-a} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (-\frac {d \left (\sqrt {-\sqrt {-a}}+\sqrt [4]{b} x\right )}{\sqrt [4]{b} c-\sqrt {-\sqrt {-a}} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (-\frac {d \left (\sqrt [4]{-a}+\sqrt [4]{b} x\right )}{\sqrt [4]{b} c-\sqrt [4]{-a} d}\right ) \log (c+d x)}{4 b^2}+\frac {(a d) \int \frac {\log \left (\frac {d \left (\sqrt {-\sqrt {-a}}-\sqrt [4]{b} x\right )}{\sqrt [4]{b} c+\sqrt {-\sqrt {-a}} d}\right )}{c+d x} \, dx}{4 b^2}+\frac {(a d) \int \frac {\log \left (\frac {d \left (\sqrt [4]{-a}-\sqrt [4]{b} x\right )}{\sqrt [4]{b} c+\sqrt [4]{-a} d}\right )}{c+d x} \, dx}{4 b^2}+\frac {(a d) \int \frac {\log \left (\frac {d \left (\sqrt {-\sqrt {-a}}+\sqrt [4]{b} x\right )}{-\sqrt [4]{b} c+\sqrt {-\sqrt {-a}} d}\right )}{c+d x} \, dx}{4 b^2}+\frac {(a d) \int \frac {\log \left (\frac {d \left (\sqrt [4]{-a}+\sqrt [4]{b} x\right )}{-\sqrt [4]{b} c+\sqrt [4]{-a} d}\right )}{c+d x} \, dx}{4 b^2} \\ & = \frac {c^3 x}{4 b d^3}-\frac {c^2 x^2}{8 b d^2}+\frac {c x^3}{12 b d}-\frac {x^4}{16 b}-\frac {c^4 \log (c+d x)}{4 b d^4}+\frac {x^4 \log (c+d x)}{4 b}-\frac {a \log \left (\frac {d \left (\sqrt {-\sqrt {-a}}-\sqrt [4]{b} x\right )}{\sqrt [4]{b} c+\sqrt {-\sqrt {-a}} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (\frac {d \left (\sqrt [4]{-a}-\sqrt [4]{b} x\right )}{\sqrt [4]{b} c+\sqrt [4]{-a} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (-\frac {d \left (\sqrt {-\sqrt {-a}}+\sqrt [4]{b} x\right )}{\sqrt [4]{b} c-\sqrt {-\sqrt {-a}} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (-\frac {d \left (\sqrt [4]{-a}+\sqrt [4]{b} x\right )}{\sqrt [4]{b} c-\sqrt [4]{-a} d}\right ) \log (c+d x)}{4 b^2}+\frac {a \text {Subst}\left (\int \frac {\log \left (1+\frac {\sqrt [4]{b} x}{-\sqrt [4]{b} c+\sqrt {-\sqrt {-a}} d}\right )}{x} \, dx,x,c+d x\right )}{4 b^2}+\frac {a \text {Subst}\left (\int \frac {\log \left (1-\frac {\sqrt [4]{b} x}{\sqrt [4]{b} c+\sqrt {-\sqrt {-a}} d}\right )}{x} \, dx,x,c+d x\right )}{4 b^2}+\frac {a \text {Subst}\left (\int \frac {\log \left (1+\frac {\sqrt [4]{b} x}{-\sqrt [4]{b} c+\sqrt [4]{-a} d}\right )}{x} \, dx,x,c+d x\right )}{4 b^2}+\frac {a \text {Subst}\left (\int \frac {\log \left (1-\frac {\sqrt [4]{b} x}{\sqrt [4]{b} c+\sqrt [4]{-a} d}\right )}{x} \, dx,x,c+d x\right )}{4 b^2} \\ & = \frac {c^3 x}{4 b d^3}-\frac {c^2 x^2}{8 b d^2}+\frac {c x^3}{12 b d}-\frac {x^4}{16 b}-\frac {c^4 \log (c+d x)}{4 b d^4}+\frac {x^4 \log (c+d x)}{4 b}-\frac {a \log \left (\frac {d \left (\sqrt {-\sqrt {-a}}-\sqrt [4]{b} x\right )}{\sqrt [4]{b} c+\sqrt {-\sqrt {-a}} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (\frac {d \left (\sqrt [4]{-a}-\sqrt [4]{b} x\right )}{\sqrt [4]{b} c+\sqrt [4]{-a} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (-\frac {d \left (\sqrt {-\sqrt {-a}}+\sqrt [4]{b} x\right )}{\sqrt [4]{b} c-\sqrt {-\sqrt {-a}} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (-\frac {d \left (\sqrt [4]{-a}+\sqrt [4]{b} x\right )}{\sqrt [4]{b} c-\sqrt [4]{-a} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \text {Li}_2\left (\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c-\sqrt {-\sqrt {-a}} d}\right )}{4 b^2}-\frac {a \text {Li}_2\left (\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c+\sqrt {-\sqrt {-a}} d}\right )}{4 b^2}-\frac {a \text {Li}_2\left (\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c-\sqrt [4]{-a} d}\right )}{4 b^2}-\frac {a \text {Li}_2\left (\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c+\sqrt [4]{-a} d}\right )}{4 b^2} \\ \end{align*}
Result contains complex when optimal does not.
Time = 0.15 (sec) , antiderivative size = 480, normalized size of antiderivative = 0.96 \[ \int \frac {x^7 \log (c+d x)}{a+b x^4} \, dx=\frac {c^3 x}{4 b d^3}-\frac {c^2 x^2}{8 b d^2}+\frac {c x^3}{12 b d}-\frac {x^4}{16 b}-\frac {c^4 \log (c+d x)}{4 b d^4}+\frac {x^4 \log (c+d x)}{4 b}-\frac {a \log \left (\frac {d \left (i \sqrt [4]{-a}-\sqrt [4]{b} x\right )}{\sqrt [4]{b} c+i \sqrt [4]{-a} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (\frac {d \left (\sqrt [4]{-a}-\sqrt [4]{b} x\right )}{\sqrt [4]{b} c+\sqrt [4]{-a} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (-\frac {d \left (i \sqrt [4]{-a}+\sqrt [4]{b} x\right )}{\sqrt [4]{b} c-i \sqrt [4]{-a} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \log \left (-\frac {d \left (\sqrt [4]{-a}+\sqrt [4]{b} x\right )}{\sqrt [4]{b} c-\sqrt [4]{-a} d}\right ) \log (c+d x)}{4 b^2}-\frac {a \operatorname {PolyLog}\left (2,\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c-\sqrt [4]{-a} d}\right )}{4 b^2}-\frac {a \operatorname {PolyLog}\left (2,\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c-i \sqrt [4]{-a} d}\right )}{4 b^2}-\frac {a \operatorname {PolyLog}\left (2,\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c+i \sqrt [4]{-a} d}\right )}{4 b^2}-\frac {a \operatorname {PolyLog}\left (2,\frac {\sqrt [4]{b} (c+d x)}{\sqrt [4]{b} c+\sqrt [4]{-a} d}\right )}{4 b^2} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.75 (sec) , antiderivative size = 175, normalized size of antiderivative = 0.35
method | result | size |
risch | \(-\frac {c^{4} \ln \left (d x +c \right )}{4 b \,d^{4}}+\frac {c^{3} x}{4 b \,d^{3}}+\frac {25 c^{4}}{48 d^{4} b}-\frac {c^{2} x^{2}}{8 b \,d^{2}}+\frac {c \,x^{3}}{12 b d}+\frac {x^{4} \ln \left (d x +c \right )}{4 b}-\frac {x^{4}}{16 b}-\frac {a \left (\munderset {\textit {\_R1} =\operatorname {RootOf}\left (b \,\textit {\_Z}^{4}-4 c b \,\textit {\_Z}^{3}+6 b \,c^{2} \textit {\_Z}^{2}-4 b \,c^{3} \textit {\_Z} +a \,d^{4}+b \,c^{4}\right )}{\sum }\left (\ln \left (d x +c \right ) \ln \left (\frac {-d x +\textit {\_R1} -c}{\textit {\_R1}}\right )+\operatorname {dilog}\left (\frac {-d x +\textit {\_R1} -c}{\textit {\_R1}}\right )\right )\right )}{4 b^{2}}\) | \(175\) |
parts | \(\frac {x^{4} \ln \left (d x +c \right )}{4 b}-\frac {\ln \left (d x +c \right ) a \ln \left (b \,x^{4}+a \right )}{4 b^{2}}-\frac {d \left (\frac {\frac {\frac {1}{4} d^{3} x^{4}-\frac {1}{3} c \,x^{3} d^{2}+\frac {1}{2} d \,x^{2} c^{2}-x \,c^{3}}{d^{4}}+\frac {c^{4} \ln \left (d x +c \right )}{d^{5}}}{b}-\frac {a \ln \left (d x +c \right ) \ln \left (b \,x^{4}+a \right )}{b^{2} d}+\frac {a \left (\munderset {\textit {\_R1} =\operatorname {RootOf}\left (b \,\textit {\_Z}^{4}-4 c b \,\textit {\_Z}^{3}+6 b \,c^{2} \textit {\_Z}^{2}-4 b \,c^{3} \textit {\_Z} +a \,d^{4}+b \,c^{4}\right )}{\sum }\left (\ln \left (d x +c \right ) \ln \left (\frac {-d x +\textit {\_R1} -c}{\textit {\_R1}}\right )+\operatorname {dilog}\left (\frac {-d x +\textit {\_R1} -c}{\textit {\_R1}}\right )\right )\right )}{b^{2} d}\right )}{4}\) | \(205\) |
derivativedivides | \(\frac {-\frac {d^{4} \left (c^{3} \left (\left (d x +c \right ) \ln \left (d x +c \right )-d x -c \right )-3 c^{2} \left (\frac {\left (d x +c \right )^{2} \ln \left (d x +c \right )}{2}-\frac {\left (d x +c \right )^{2}}{4}\right )+3 c \left (\frac {\left (d x +c \right )^{3} \ln \left (d x +c \right )}{3}-\frac {\left (d x +c \right )^{3}}{9}\right )-\frac {\left (d x +c \right )^{4} \ln \left (d x +c \right )}{4}+\frac {\left (d x +c \right )^{4}}{16}\right )}{b}-\frac {a \,d^{8} \left (\munderset {\textit {\_R1} =\operatorname {RootOf}\left (b \,\textit {\_Z}^{4}-4 c b \,\textit {\_Z}^{3}+6 b \,c^{2} \textit {\_Z}^{2}-4 b \,c^{3} \textit {\_Z} +a \,d^{4}+b \,c^{4}\right )}{\sum }\left (\ln \left (d x +c \right ) \ln \left (\frac {-d x +\textit {\_R1} -c}{\textit {\_R1}}\right )+\operatorname {dilog}\left (\frac {-d x +\textit {\_R1} -c}{\textit {\_R1}}\right )\right )\right )}{4 b^{2}}}{d^{8}}\) | \(209\) |
default | \(\frac {-\frac {d^{4} \left (c^{3} \left (\left (d x +c \right ) \ln \left (d x +c \right )-d x -c \right )-3 c^{2} \left (\frac {\left (d x +c \right )^{2} \ln \left (d x +c \right )}{2}-\frac {\left (d x +c \right )^{2}}{4}\right )+3 c \left (\frac {\left (d x +c \right )^{3} \ln \left (d x +c \right )}{3}-\frac {\left (d x +c \right )^{3}}{9}\right )-\frac {\left (d x +c \right )^{4} \ln \left (d x +c \right )}{4}+\frac {\left (d x +c \right )^{4}}{16}\right )}{b}-\frac {a \,d^{8} \left (\munderset {\textit {\_R1} =\operatorname {RootOf}\left (b \,\textit {\_Z}^{4}-4 c b \,\textit {\_Z}^{3}+6 b \,c^{2} \textit {\_Z}^{2}-4 b \,c^{3} \textit {\_Z} +a \,d^{4}+b \,c^{4}\right )}{\sum }\left (\ln \left (d x +c \right ) \ln \left (\frac {-d x +\textit {\_R1} -c}{\textit {\_R1}}\right )+\operatorname {dilog}\left (\frac {-d x +\textit {\_R1} -c}{\textit {\_R1}}\right )\right )\right )}{4 b^{2}}}{d^{8}}\) | \(209\) |
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\[ \int \frac {x^7 \log (c+d x)}{a+b x^4} \, dx=\int { \frac {x^{7} \log \left (d x + c\right )}{b x^{4} + a} \,d x } \]
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Timed out. \[ \int \frac {x^7 \log (c+d x)}{a+b x^4} \, dx=\text {Timed out} \]
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\[ \int \frac {x^7 \log (c+d x)}{a+b x^4} \, dx=\int { \frac {x^{7} \log \left (d x + c\right )}{b x^{4} + a} \,d x } \]
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\[ \int \frac {x^7 \log (c+d x)}{a+b x^4} \, dx=\int { \frac {x^{7} \log \left (d x + c\right )}{b x^{4} + a} \,d x } \]
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Timed out. \[ \int \frac {x^7 \log (c+d x)}{a+b x^4} \, dx=\int \frac {x^7\,\ln \left (c+d\,x\right )}{b\,x^4+a} \,d x \]
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